critical path
Submitted by vijayavadrevu on Fri, 05/24/2013 - 12:23
1) The following provides information on a particular task in your project:
Early Start(ES): 25 days
Late Start(LS): 30 days
Early Finish(EF): 50 days
Late Finish(LF): 55 days
Based on this information, you can deduce that:
- The task is on the critical path.
- The project may get delayed.
- The project float is 5 days.
- The task is not on the critical path
Forums:


san
Fri, 05/24/2013 - 12:29
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Ths should be 4. Task is not
Ths should be 4. Task is not on the critical path. Since float is 5 days this is not on the critical path. Ideally , float should be 0 for critcal paths
eng_mut
Fri, 05/24/2013 - 12:34
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4?
4?
vijayavadrevu
Fri, 05/24/2013 - 14:42
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yes, option 4 is correct
yes, option 4 is correct
jvleminc
Wed, 05/29/2013 - 15:26
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4
Only info about one task is given, hence 2 and 3 do not apply.
Task Float = LS - ES = 5, hence not on the critical path => 4
cnppmp
Wed, 05/29/2013 - 18:26
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option 4 , this simple one
option 4 , this simple one, as the float doesn't refer to Critical path.
Regards
CN Patil