Probability Question

In using the "rule of seven", a quality control approach, it is generally accepted that a process is out of control when in a production run seven or more samples lay on one side of the mean on the control chart. what is the probability that a run of seven samples, appearing on either side of the process mean is due to random variable?

1. 0.16%
2. 0.78%
3. 1.56%
4. 1.99%

correct answer is 3. can somebody please explain how we get this.

Thanks.

The probability of 7 consecutive points to lie on one side of mean is (1/2)^n=(1/2)^7=0.0078*100=0.78. But this value is for 7 Po ints to lie on one side of mean considering either sides it shud be 1.56.

Does this explain n clarify. Or refer linkhttp://projectmanagement.ittoolbox.com/groups/career/projectmanagement-c...

Thanks

Very well understood..thank u.

You are welcome :)