Probability Question
Submitted by Nabs on Sun, 09/14/2014 - 08:42
In using the "rule of seven", a quality control approach, it is generally accepted that a process is out of control when in a production run seven or more samples lay on one side of the mean on the control chart. what is the probability that a run of seven samples, appearing on either side of the process mean is due to random variable?
1. 0.16%
2. 0.78%
3. 1.56%
4. 1.99%
correct answer is 3. can somebody please explain how we get this.
Thanks.
Forums:


dipti1pmp
Sun, 09/14/2014 - 17:37
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here u go
The probability of 7 consecutive points to lie on one side of mean is (1/2)^n=(1/2)^7=0.0078*100=0.78. But this value is for 7 Po ints to lie on one side of mean considering either sides it shud be 1.56.
Does this explain n clarify. Or refer linkhttp://projectmanagement.ittoolbox.com/groups/career/projectmanagement-c...
Thanks
Nabs
Mon, 09/15/2014 - 19:13
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Thank you
Very well understood..thank u.
dipti1pmp
Tue, 09/16/2014 - 07:31
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You are welcome
You are welcome :)