**HeadFirst question **
Submitted by sam_jain on Sat, 05/12/2012 - 13:56
From Headfirst 200 question
106. Given this portion of the network diagram to the right,
what’s the LF of activity F?
( not able to attach the picture)
Correct Answer :
106. Answer: A
It’s just easy to calculate the late finish (LF) of an activity in a network diagram. Look at the
following activity, take its LS (late start), and subtract one. If there’s more than one following activity,
use the one with the lowest LS. So for activity F in the question, the following activities are G, with
an LS of 17, and H, with an LS of 11. So the LF of F is 11 - 1 = 10.
My Answer : B
As per Rita Book , we do not have to do LS(predecessor) = LF(successor) - 1 , just LF of predecessor activity will become LS of successor.